There are 6term in a Gp. Prove that the product of first and last term of the gp is equal to the product of the 3rd and 4rd team.
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the 6 terms in GP : 
Product of first and 6th term =
Product of 3rd and 4th term =
Hence proved they are equal
Product of first and 6th term =
Product of 3rd and 4th term =
Hence proved they are equal
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