Question

There are 7 electrons in the third shell of an element a, write it's subshell electronic configuration

Answer 1

Answer:

1s² 2s² 2p⁶ 3s² 3p⁵

Explanation:

K shell = s

L shell = sp

M shell = 7 (given) subshells present in M shell is spd so the spd subshell contains 7 electrons

3s² 3p⁵ = 7

Answer 2

The subshell electronic configuration is $3s^23p^5$.

• The first shell is the K shell has a 1s subshell and can have 2 electrons.
• The second shell is the L shell has 2s and 2p subshells and can have 8 electrons.
• The third shell is the M shell has 3s, 3p and 3d subshells and can have 18 electrons.
• Thus M shell has 7 electrons and its electronic configuration is as follows $3s^23p^5$.