Math, asked by 7axra, 10 months ago

There are 7 people taking part in a raffle.

Ann, Bob, Jim, Lena, Omar, Ravi, and Soo.

Suppose that prize winners are randomly selected from the 7 people.

Compute the probability of each of the following events.

Event A: The first four prize winners are Jim, Ravi, Soo, and Lena, regardless of order.

Event B: Bob is the first prize winner, Lena is second, Jim is third, and Soo is fourth.

Write your answers as fractions in simplest form.

P[A]=

P[b]=

Answers

Answered by Keertikaushik009
1

Answer:

P(A) = 4/7

P(B) = 53/70

Step-by-step explanation:

P(A) = 4/7 becz no. Of obs. is 4 which is divisible by tolal no. of obs.

P(B) = 1/7+1/6+1/5+1/4

= 638/840

=53/70

Similar questions