Question

There are 7 trout fish in a pond, and the population doubles every year. Find the population after t years.

Answer 1

Final Answer :
$7( {2}^{t} - 1)$
Steps:
1) No. of fishes :
No. of fishes in 1 year = 7
No. of fishes in 2 years = 14
No. of fishes in 3 years = 28

Therefore,
7, 14 ,28 ,.........t terms

First term, a = 7
Common ratio, r = 2
No. of terms, n = t

2) t th term,
$a(t) = a {r}^{t - 1} = 7 \times {2}^{t - 1}$
Therefore,
After t years, No. of fishes in pond is
$\boxed {7 \times {2}^{t - 1} }$

Answer 2

Answer:

7(2)^t

Step-by-step explanation: