Question

There are 72, 108 and 132 pears in three different baskets.
What is the largest group into which the pears can be split, if
they have to be arranged equally?​

Answer 1

Answer:

12

Step-by-step explanation:

HCF OF 72, 108 and 132 = 12

Answer 2

Given:

There are 72, 108 and 132 pears in three different baskets.

To find:

The largest group into which the pears can be split, if  they have to be arranged equally.

Solution:

There are 72, 108 and 132 pears in three different baskets.

We can find the largest group into which the pears can be split, if  they have to be arranged equally by finding the HCF of 72 , 108 and 132

72 = 2 × 2 × 2 × 3 × 3

108 = 2 × 2 × 3 × 3 × 3

136 = 2 × 2 × 3 × 11

HCF of 72 , 108 and 132 is 2 × 2 × 3 = 12

The largest group into which the pears can be split, if  they have to be arranged equally is 12

Final answer:

The largest group into which the pears can be split, if  they have to be arranged equally is 12