there are 720 students in a school the ratio of the number of boys to girl is 7:2 . if 40 new boys are admitted, find how many new girls should be admitted so that the ratio of the number of boys to the number of girls may be changed to 10:3
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No of students = 720
Ratio between girls and boys = 7 : 2
Let the common multiple be x.
So, no of girls = 2x and no of boys = 7x
-> 7x + 2x = 720
=> 9x = 720
=> x = 720 / 9
=> x = 80
Therefore, no of girls = 2 x 80 = 160 and no of boys = 7 x 80 = 560
Given,New boys added = 40
So, no boys = 560 + 40 = 600
Let y girls be added.
So, no of girls = (160 + y)
A.C.Q., (160 + y) / 600 = 10 / 3
=> 3 ( 160 + y ) = 10*600
=> 480 + 3y = 6000
=> y = (6000-480)/3
=> y=1840
so, 1840 girls are to be admitted to make the ratio of boy: girl=10:3
msusanna53:
sry it is wrong answer
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0
Answer:
y= 20
Step-by-step explanation:
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