Question

There are 8.4*10^22 free electrons per cm^3 in copper. The current in the wire is 0.21 A . then the drift velocity of electrons in copper wire of 1mm^3 cross section will be

Answer 1

Answer:

DRIFT VELOCITY ( VD ) = 1.56 ×10^-10 m/s

Explanation:

★ CURRENT ELECTRICITY ★

★ GIVEN ;

» No. of Free Electrons ( n ) = 8.4 × 10²² ê

» Current ( i ) = 0.21 Ampere

» Area of Cross - Section ( A ) = 1 mm³ ≈ 1000 cm³.

★ » DRIFT VELOCITY ( Vd ) = ???

_______ [ BY USING FORMULA ] ______

[ $current \: ( \: i \: ) = \: n \: \times \: e \: \times a \: \times vd$ ]

★ [ Drift Velocity ] Vd = i / n × e × A

» Vd = [ 0.21 ] / [ 8.4 × 10²² × 1.6 × 10^-19 × 1000 ]

» Vd = [ 0.21 ] / [ 8.4 × 1.6 × 10^6 ]

» Vd = [ 0.21 ] / [ 13.44 × 10^6 ]

» Vd = [ 10^-6 ] / 64

★ » Vd = 1.56 × 10^-8 cm / s

[ OR ]

★→ Vd = 1.56 × 10^-10 m / s

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ANSWER :- HENCE ; Drift Velocity ( Vd )

Drift Velocity ( Vd ) for 0.21 A current is ;

♣ Vd = 1.56 × 10^-10 m / s ♥