Question

there are 8 equal resistance R. Two are connected in parallel such four groups are connected in series the total resistance of the system will be​

Answer 1

Explanation:

Two resistors are connected in parallel :-

1/Rp = 1/R + 1/R

1/Rp = 1 + 1 / R

1/Rp = 2/ R

Rp = R / 2

Now rest 6 resistors are in series and Rp is also in series now

Req = R + R + R + R + R + R + R/2

Req = 6R + R/2

Req = 12R + R / 2

Req = 13 R / 2

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