There are 8 Persons to be arranged in one car. Out of 8 Persons three of them are
Drivers and rest are non-Drivers. Arrange 5 persons in one car.
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Explanation:
There are 8 persons and 3 different taxis with 3 seats. Since, not more than 3 can be accommodated in a taxi, we can form 3 groups in 3 taxis. Group of 3, another group of 3 and the last group of 2. The first group can be chosen in C(8,3)=56 ways. Similarly, the 2nd group can be chosen out of remaining 5 in C(5,3)=10 ways and the last group can be chosen in C(2,2)=1 way. So, in all there will be 56∗10∗1=560 ways of group selection. But these 3 groups can be arranged among themselves in 3!=6 ways. Hence, the total arrangement will be 560∗6=3360 .
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Answer:
three drivers are on car and five person can be arranged on a one car as they are not drivers.
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