Question

there are 8 question in examination paper and each question has an alternative. the number of ways in which a student can give his answer?​

Answer 1

Step-by-step explanation:

There are 8 questions in paper

Since each question has an alternative the student at least attain 8/2 = 4 questions.

If student answer 4 questions

8C4 = 8!/4!4!

= 8 × 7 × 6 × 5 / 1× 2 × 3× 4

= 70

If student answer 5 questions

8C5 = 8!/5!3!

= 8 × 7 × 6/1 × 2× 3

= 56

If he answer 6 questions

8C6 = 8!/6!2!

=8×7/2

=28

If he answer 7 questions

8C7 = 8!/7!1!

= 8

If he answers 8 questions

8C8 = 1

Total no. of ways = 70 + 56 + 28 + 8 + 1

= 163

Total no. of ways = 163 .

THANKS

Answer 2

Answer:163

Step-by-step explanation:

total questions in examination paper = 8

each question has an alternative so , 8/2 = 4

8c4 = 70

now 8c5 = 56

now 8c6 = 28

now 8c7 = 8

now 8c8= 1

so total 70+56+28+8+1 = 163