Question

There are 84 apples, 120 oranges, and 138 mangoes. These are to be arranged in heaps containing the same number of fruits. Find the greatest number of fruits possible in each heap. How many heaps are formed?

Answer 1

$\huge\sf\pink{Answer}$

☞ Your Answer is 6 Heaps

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$\huge\sf\blue{Given}$

✭ There are 84 Apples 120 Oranges and 138 Mangoes

✭ They are arranged as heaps with the same number of fruits

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$\huge\sf\gray{To \:Find}$

◈ How many Heaps are formed?

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$\huge\sf\purple{Steps}$

So here we simply have to find the HCF of 84,120,138, Here we shall use the factorisation method,that is,

➝ $\sf 84 = 2 \times 2 \times 7 \times 3$

➝ $\sf 120 = 2 \times 2 \times 2 \times 5 \times 3$

➝ $\sf 138 = 2 \times 3 \times 23$

So the HCF of 2 Numbers is the Product of the least power of the common factors,here,

➢ $\sf HCF = 2 \times 3$

➢ $\sf \orange{HCF = 6}$

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Answer 2

Solution :-

Given :

• Number of Apples =84
• Number of Oranges =120
• Number of Mangoes =138
• Arranged in heaps containing the same number of fruits.

To Find :

• Number of formed heaps.

Head to the question :

Here we simply have to find out the HCF of 84,120,138, Here we shall use the factorisation method :

$:\implies { \sf 84 = 2 \times 2 \times 3 \times 7}\\ \\ :\implies { \sf 120 = 2 \times 2 \times 2 \times 3 \times 5}\\ \\ :\implies {\sf 138 = 2 \times 3 \times 23}$

$:\implies {\tt {HCF = 2 \times 3}}\\ \\ :\implies{\tt{ 2\times 3}} \\ \\ :\implies {\tt {HCF = 6}}$

Therfore , number of formed heaps = 6