Question

there are 9 cards bearing numbers 1 2 3 4.....89 in a bag a card is drawn at random from the bag find the probability of getting a card having a multiple of 3​

Answer 1

Answer:

There are a total of 10 cards in the bag, all bearing even numbers on them.

A. Since the only even prime number is 2 and there is exactly one card which bears this number, the probability of drawing a card with a prime number on it is 101=0.1

B. There are 5 numbers divisible by 4, they are 4,8,12,16,20. So, the probability of drawing a card which has a number divisible by 4 on it is 105=0.5

C. There are 3 numbers which are multiples of 6, they are 6,12,18. So, the probability of drawing a card which has a number divisible by 6 on it is 103=0.3

D. There is no odd-numbered card in the bag. So the probability of drawing a card with an odd number on it is 0.