Question

there are 9 chairs in a room on which 6 persons are to be seated out of which one is guest with one specific chair.ib how many ways they can seat
​

Answer 1

Answer:

6720

Step-by-step explanation:

Out of 9 chair 1 chair is for 1 guest so now total chair is 8 and person is 5.

5 people can occupy these chairs in P(8,5) = 8! / 3! = 6720 ways

Answer 2

There are 6720 ways.

Step-by-step explanation:

Since we have given that

Number of chairs = 9

Number of persons = 6

We need to find the number of ways in which one is guest with one specific chair.

So, Number of chair becomes = 9-1 =8

Number of persons = 6-1 =5

So, number of ways would be

$^8P_5=6720$

Hence, there are 6720 ways.

# learn more:

Two persons enter a room in which five seats

are vacant. In how many ways can they occupy

the seats?​

https://brainly.in/question/12104168