Question

there are 9 students (5 boys 4 girls) in how many ways two medals can be distributed. (no one get both)

Answer 1

Hi friend!!!

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Given,there are 9 students (5 boys 4 girls)

number of ways two medals can be distributed. (no one get both) is 9p2

=9×8=72 ways

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I hope this will help u ;)

Answer 2

Answer:

There are 36 ways to distribute 2 medals .

Step-by-step explanation:

Given :There are 9 students (5 boys 4 girls)

To Find : How many ways two medals can be distributed. (no one get both)

Solution :

We will use combination over here .

Total no. of students = 9

No. of medals = 2

We are given that no one get both.

Formula : $^nC_r = \frac{n!}{r!(n-r)!}$

Substitute n = 9

r = 2

No. of ways 2 medals can be distributed = $^{9}C_{2}= \frac{9!}{2!(9-2)!}$

                                                                    = $36$

Hence There are 36 ways to distribute 2 medals .