Math, asked by jasvir90, 1 year ago

There are a certain number of tins that are filled with milk from a machine. If the machine fills at the
rate of 5 tins/min, 3 tins are left empty; at the rate of 8 tins/min, 5 tins are left empty and the rate of 7
tins/min, 4 tins are left empty. In this setup it is possible to have N different number of tins. Find N,
ginve that (100 <N< 1000). There is no leakage or wastage of milk and the machine can work only
for integral number of minutes.
A. 133
B. 293
LC. 613
D. 648

Answers

Answered by arohi2545

the integral number will be 293

jasvir90: will you please explain it

jasvir90: thanks for your response

arohi2545: yes u have to add what is the first two digit u have to see them if any is same the is the integral number i

arohi2545: it is common sense question

jasvir90: the answer is 613 . it can be solved by option easily. i am concerning about concept

arohi2545: ok its common sense u r not trying perfectly

Answered by Anonymous

Given

A certain number of tins that are filled with milk from a machine

To find

We have to find N , where N is the number of tins

Solution

We can simply solve this mathematical problem by using the following mathematical process.

Here, the machine fills at the rate of 5 tins/min, 3 tins are left empty; at the rate of 8 tins/min, 5 tins are left empty and and the rate of 7 tins/min, 4 tins are left empty.

Using CRT

5A+3=8B+5

5A = 8B + 2, B = 1 and A = 2 , the AP is of the form 40 K + 13

⇒40K + 13 = 7C + 4

⇒7C = 40K+9

⇒7c = 5K + 2

⇒ K=1 and C=7. The AP is of the form 53+280N

Hence, three digit numbers possible in this AP are 53 + 280 = 333 ,

53 + 2(280) = 613 and 53 + 3(280) = 893.

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