There are 'b' bricks that need to stacked after k' of them in terms 'b'and 'k', what percent of the bricks have not yet been stacked
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100([b-k]/b) percent of the bricks have not yet been stacked
It is given that the total number of bricks that are needed to be stacked = b.
Number of bricks which have been stacked = k.
So, the number of bricks that havent been stacked is equal to (Total bricks - number of stacked bricks)
= (b - k)
To represent the percentage of bricks which are unstacked.
It is equal to [(Unstacked bricks / Total bricks) × 100]%
= [ (b-k)/b × 100]%
= 100([b-k]/b) %
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