There are bicycles and tricycles parked along a road. There are 29 wheels and 11 riders. How many bicycles are there?
Answers
Answer:
let number of bicycles is x
and number of tricycles is y
2x+3y = 29----------------------------eq.1
x+y = 11---------------------------------eq.2
eq.2 multiplied by 3
3x+3y=33------------------------------eq.3
eq.1 - eq.2 => 2x+3y -3x-3y =29 -33
=> -x=-4
=> x=4 put this value in eq.2
and we get => y = 7
therefore
Bicycles = 4
Tricycles = 7
Answer:
There are 4 bicycles.
Step-by-step explanation:
Given: There are some bicycles and tricycles parked.
Total number of wheels = 29 and riders = 11.
To find: The number of bicycles.
Solution: There are totally 29 wheels for both bicycle and tricycle.
we can split this 29 wheels as 21+8. 29 can also be splitted in many ways but number of riders won't be 11.
Bicycle has 2 wheels and tricycle has 3 wheels.
So we will divide this 21 and 8 using 3 and 2.
21 ÷ 3 = 7 and 8 ÷ 2= 4. That means 7 tricycles with 21 wheels and 4 bicycles with 8 wheels. Thus there are 7+4=11 riders.
Therefore, there are 4 bicycles.
Another method:
Let number of bicycles be a and number of tricycles be b.
Total number of riders is 11 ⇒ a+b = 11----- eq.(1)
total number of wheels is 29 ⇒2a+3b=29---eq.(2)
subtracting eq.(2) from (1), we get
eq.(1)×2 , 2a+2b =22
eq.(2) , 2a+3b = 29
-b = -7
b = 7
So number of tricycles is 7.
put b=7 in eq.(1),
a +7 = 11 ⇒ a = 11 - 7 = 4.
Therefore number of bicycles is 4.