Question

There are certain 2-digit numbers. The difference between
the number and the one obtained on reversing it is always
27. How many such maximum 2-digit numbers are there?

Answer 1

Answer:

there are six such numbers

Step-by-step explanation:

Let the numbers be of the form xy and yx, i.e. 10x + y and 10y + x (where y > x) As per the question, (10y + x) – (10x + y) = 27 Or 9y – 9x = 27 Or y – x = 3 Or y = x + 3 So, possible sets of the value of x and y are: (1, 4), (2, 5), (3, 6), (4, 7), (5, 8) and (6, 9), i.e. 6 such numbers are there.