Math, asked by parasnandu, 1 month ago

There are d deer and p pheasants in the woods. How many legs in total? (d and p variables)​

Answers

Answered by RaghavYadavilli
0

Answer:

4d + 2p

Step-by-step explanation:

As deer have 4 legs and pheasants have 2 legs

Therefore 4(d) + 2(p)

4d +2p

Answered by ppiyush3726
1

soo i think that will be 4d +2p

if you mean peasants by pheasants.

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