Question

There are deer and peacocks in a zoo. The number of their heads is 80 and the total number of legs is 200. how many peacocks are there?

Answer 1

Let there be X deer and Y peacock.
Then.....4X+2Y=200............(i)
and ......X+Y=80.................(ii)
Solving (i) and (ii), we get,
=20 Y=60


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Answer 2

Hi Friend !!!

=================

let the number of peacoks be x

and deer be y

x+y = 80---------(1)

2x+4y = 200

2(x+2y) = 200

x+2y = 100---------------(2)

subract 1 from 2

x+2y-x-y = 100 - 80

y = 20

x+y = 80

x+20 = 80

x = 80-20

x = 60

So the number of peacocks are 60

Hope it helps u:-)