Question

there are deers and peacocks in a zoo. by counting their heads are 80. the number of legs are 200. how many peacocks are there

Answer 1

there are 80 peacocks in the zoo

Answer 2

let the no. of deers be x
no of peacocks y
=> x+y =80. eq1
4x +2y= 200. eq2
from eq1 ,
x=80-y------------- put value of x in eq2
=> 4(80-y)+2y=200
after solving...
y(no. of peacocks ) is 60