Question

There are eight marbles in a bag. Four marbles are blue (B), two marbles are red

(R) and two marbles are green (G)

Steve takes a marble at random from the bag.

(i) What is the probability that Steve will take a blue marble.

(ii) What is the probability that Steve will take a green marble. (iii) What is the probability that Steve will take a yellow marble.​

Answer 1

Given:-

• Four marbles are blue (B)
• Two marbles are red (R)
• Two marbles are green (G)

To find:-

• The probability of blue marble to be chosen
• The probability of green marble to be chosen
• The probability of yellow marble to be chosen

Solution:-

i) Probability of Blue marble

There are 4 blue marbles

Total marbles is 8

P(E) = 4/8 =1/2

ii) Probability of Green marble

There are 2 green marble

Total marble is 8

P(E) = 2/8 = 1/4

iii) Probability of Yellow marble

There are no marble

Total marble is 8

P(E) = 0/8 = 0

Answer 2

Step-by-step explanation:

i) Probability of Blue marble

There are 4 blue marbles

Total marbles is 8 P(E) = 4/8 =1/2

ii) Probability of Green marble

There are 2 green marble

Total marble is 8

P(E) = 2/8 = 1/4 =

iii) Probability of Yellow marble

There are no marble

Total marble is 8

P(E) = 0/8 = 0