Math, asked by cavin8466, 8 months ago

There are exactly two points on the ellipse whose distance from its centre is same

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Answered by Anonymous
1

Answer:

There are exactly two points on the ellipse(x^2/a^2)+(y^2/b^2)=1, whose distance from its center is same and b equal to 1/? 2(?(a^2+2b^2)). The eccentricity of the ellipse is. ... Note :here vertex has the coordinate (a,0) so its distance from the centre whis has been assumed to be (0,0) is a.

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