Question

there are few adults and children in a restaurant. if 3/8 of the people in the restaurant are adults and there are 90 more children than adults, then how many children are there in the restaurant?

Answer 1

let x be the total no. of people

adult= total-(adult+90)           {adult+90 is no. of children}

3x/8=x-(3x/8+90)
3x/8=x-3x/8-90
3x/8=5x/8-90
90=5x/8-3x/8
90=2x/8
90*8/2=x
360=x

total people 360

adult- 3/8*360=135

children- 135+90=225

Answer 2

Answer: There are 225 children in the restaurant.

Step-by-step explanation:

Since we have given that

Let the total number of people be x

Number of people in the restaurant are adults = $\dfrac{3}{8}$

Number of people in the restaurant are children = $(1-\dfrac{3}{8})x=\dfrac{5}{8}x$

According to question, there are 90 more children than adults.

so, it becomes

$\dfrac{5x}{8}-\dfrac{3x}{8}=90\\\\\dfrac{2x}{8}=90\\\\\dfrac{x}{4}=90\\\\x=90\times 4\\\\x=360$

So, Number of children are in the restaurant is given by

$\dfrac{5}{8}\times 360\\\\=225$

Hence, there are 225 children in the restaurant.