Question

There are five boxes in a cargo. The weight of the first box is 200 kg and the weight of the second box is 20 % higher than the weight of the third box, whose weight is 25% higher than the weight of the first box. The fourth box which weighs 350 kg is 30% lighter than the fifth box. Find the difference in the average weight of the four heaviest boxes and four lightest boxes.



a. 75 kg



b. 51.5 kg



c. 65 kg



d. 37.5 kg

Answer 1

Answer: a. 75 kg

Step-by-step explanation:

Let the boxes be named as A, B, C, D, E

A = 200 kg

B = Weight of C + 20% of weight of C

C = weight if A + 25% if weight of A = 200 + [(25/100) * 200] = 200 + 50 = 250 kg

=> B = 250 + [(20/100) * 250] = 250 + 50 = 300 kg

D = 350 kg = weight of E - [(30/100)*weight if E]

=> 350 = E - 30/100*E = 70/100*E

=> E = 350 * 100/70 = 500

E = 500 kg

4 heaviest boxes = B, C, D, E

Average = (300 + 250 + 350 + 500) / 4 = 1400 / 4 = 350

4 lightest boxes = A,B,C,D

Average = (200 + 300 + 250 + 350) / 4 = 1100 / 4 = 275 kg

Difference between the averages = 350 - 275 = 75kg

Therefore answer = a. 75kg

Please brainlist my answer, if helpful!