There are five boys of McGraw-Hill Mindworkzz and three girls of I.I.M Lucknow who are sitting together to discuss a management problem at a round table. In how many ways can they sit around the table so that no two girls are together?
Answers
Answered by
0
Given:
Total number of boys = 5
Total number of girls = 3
To Find:
Ways in which no two girls sit together
Solution:
Five boys can be places in ways = 5! or 5p5
The combination will be = b - b - b - b - b
= 5 × 4 × 3 × 2 × 1
= 120
Three girls can be seated as = 6p3
= 6! / ( 6 - 3)!
= 6!/3!
= 6 × 5 × 4 × 3 × 2 × 1 / 3 × 2 × 1
= 120
Thus, the total number of ways in which they can sit
= 120 × 120
= 14400
Answer: There are 14400 possible ways
Answered by
4
Answer:
5! x 3! x 2! = 1440
Step-by-step explanation:
| B | G | B | G | B || G | B | B |
Boys can be seated in 5! ways.
Girls can be seated in 3! ways.
after "||" symbol || G | B | B | can be arranged in 2! ways.
so the answer is 5! x 3! x 2! = 1440.
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