Question

There are five different boxes and seven different balls. All the seven balls are to de distributed in the five boxes placed in a row so that any box can recevie an
number of balls. In how many ways can these balls be distributed into these boxes if ball 2 can be put into either box 2 or box 4?​

Answer 1

Answer:

Correct option is

A

9

1 ball for box 2 & 1 for box 4 in 7C1×5C1=42ways

Remaining 5 balls are to be put in 3 boxes =3×(25−2)+3×1=93

Total =42×93=3906