There are five electric appliances, viz. electric heater and electric lamp, an electric fan, computer and an exhaust fan are connected in parallel in a household. The resistance electric appliances are 40Ω, 5Ω, 8Ω, 20Ω and 10Ω respectively. If an electric current of 240 V is flowing through the circuit then find:
a. Total resistance through the circuit
b. Total electric current (I) through the circuit and
c. the current through each of the resistor.
Answers
Solution;
a.
given,
R1=40ohm,R2=5ohm,R3=8ohm,R4=20ohmand R5=10ohm.
Total resistance
1/R=1/R1+1/R2+1/R3+1/R4+1/R5
1/R=1/40+1/5+1/8+1/20+1/10
1/R=(1+8+5+2+4)/40
1/R=20/40
1/R=1/2
R=2ohm
So, Total resistance is 2ohm.
b.
we know that,
V=IR
240=I*2
I=120A
So, electric current is 120A.
c.
current through each resistor as follows;
we know that,
V=IR
I=V/R
I1=240/40
I1=6A
I2=240/5
I2=48A
I3=240/8
I3=30A
I4=240/20
I4=12A
I5=240/10
I5=24A
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Answer:
Explanation:
Solution;
a.
given,
R1=40ohm,R2=5ohm,R3=8ohm,R4=20ohm and R5=10ohm.
Total resistance
1/R=1/R1+1/R2+1/R3+1/R4+1/R5
1/R=1/40+1/5+1/8+1/20+1/10
1/R=(1+8+5+2+4)/40
1/R=20/40
1/R=1/2
R=2ohm
So, Total resistance is 2ohm.
b.
we know that,
V=IR
240=I*2
I=120A
So, electric current is 120A.
c.
current through each resistor as follows;
we know that,
V=IR
I=V/R
I1=240/40
I1=6A
I2=240/5
I2=48A
I3=240/8
I3=30A
I4=240/20
I4=12A
I5=240/10
I5=24A
I hope it helpful for you!