Question

There are five members A, B, C, D and E in a family. Ratio of ages of A and B five years ago was 3: 4. Sum of ages of D and E five years hence will be 90. If C were born four years later than his actual date of birth, present Age of C would be half to that of present age E.

WHAT IS THE AGE OF D FOUR YEARS AGO , IF THE CURRENT AGE OF C IS 27 YEARS

EXPLAIN WITH STEPS ​

Answer 1

Answer:

Ratio of ages of A and B five years ago was 3: 4. Sum of ages of D and E five years hence will be 90

Step-by-step explanation:

ask your maths teacher

Answer 2

Concept: Equations are mathematical expressions with an equality sign in between the right-hand side and the left-hand side.

Given: There are five members A, B, C, D, and E in a family.
The ratio of ages of A and B five years ago was 3: 4.
Sum of ages of D and E five years hence will be 90.
The current age of C is 27.
C was born four years later than his actual date of birth. And the present age of C would be half that of the present age of E.

Find: Determine the age of D four years ago.

Solution: The sum of the ages of D and E five years hence will be 90.
That means (D + 5) + (E + 5) = 90
⇒ D + E = 90-10 = 80

Current age of C is 27.
C was born four years later than his actual date of birth. And the present age of C would be half that of the present age of E.

So, (27 - 4) = E/2
E = 46 years

From D+E=80 we get
D = 34 years

Hence, the age of D four years ago is (34-4) = 30 years.

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