Question

There are five points on a sheet paper ,such that no three are collinear . What is the number of line selement that can be drawn by joining the point in Pairs?

Answer 1

The number of lines that can be drawn by joining n points (no 3 are collinear) is nC2
By applying the formula we get
No. of lines = 5C2 = 5!/3!.2! = 10




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Answer 2

Answer:

There are $10$ ways to draw lines among $5$ points.

Step-by-step explanation:

Given that there are $5$ points such that no $3$ are collinear.

We know that a line segment consists of $2$ points.

Here, since no $3$ points are collinear, no two pair of points will create the same line segment.

So, to find the number of line segments which can be drawn, we can use the formula $^5C_2$

$^5C_2=\frac{5!}{((5-2)!2!}$

$=\frac{5!}{3!*2!} \\\\=\frac{5*4*3*2*1}{(3*2*1)(2*1)}$

$=10$

Hence, there are $10$ ways to draw lines among $5$ points.