There are five rods K,LM,N and O. The weight of L is equal to the weight of K and M taken together. The weight of O is K and N taken together. The weight of M is twice the weight of K. The weight of N is the weight of M. If the weight of N is 90 kg. What will be the weight of O?
Answers
Answer:
The weight of O is 90 kgs.
Step-by-step explanation:
Given,
The weight of O is twice L
O = 2L --- Eq (1)
The weight of L is equal to the weights of K and M together
L = K+M --- Eq (2)
The weight of M is twice the weight of K
M = 2K --- Eq (3)
The weight of N is three times the weight of M
N = 3M --- Eq (4)
Given, N = 90 kg --- Eq (5)
From Eq (4), 3M = 90
M = 30 --- Eq (6)
Substitute Eq (6) in Eq (3)
30 = 2K
K = 15
Substitute the value of K and M in Eq (2)
L = 15 + 30 = 45
Now, substitute the value of L in Eq (1)
O = 2(45) = 90 kg.
Therefore, The weight of O is 90 kg.
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Given : Five rods K, L, M, N and O.
weight of L is equal to the weights of K and M taken together
weight of M is twice the weight of K
weight of N is three times the weight of M ( correction)
Ref: https://brainly.in/question/26675485
weight of N is 90 kg
The weight of O is K and N taken together
To Find : Weight of O
Solution:
weight of N is the weight of M
N = 90 kg
N = 3M
=> 90 = 3M
=> M = 30
Weight of M is 30 kg
weight of M is twice the weight of K
=> M = 2K
=> 30 = 2K
=> K = 15
Weight of K is 15 kg
weight of L is equal to the weights of K and M taken together
L = K + M
=> L = 15 + 30
=> L = 45
Weight of L is 45 kg
The weight of O is K and N taken together
O = K + N
=> O = 15 + 90
=> O = 105
Weight of O is 105 kg
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