there are five terms in an ap the sum of these terms is 55 and the fourth term is 5 more than the sum of the first two terms find the terms of a p
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Let the 5 terms be (a - 2d), (a - d), a , (a + d), (a + 2d)
Sum of all terms = 5a = 55
⇒ a = 11
4ᵗʰ term = 5 + (1ˢᵗ term + 2ⁿᵈ term)
⇒ a + d = 5 + a - 2d + a - d
⇒ 4d = 5 + a
⇒ d = 16/4 = 4
On substituting the values of a and d we get the terms as 3, 7, 11, 15, 19
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