Question

there are five terms in an ap the sum of these terms is 55 and the fourth term is 5 more than the sum of the first two terms find the terms of a p​

Answer 1

Answer:

11 itvis the answer osf this question

Answer 2

Answer:

3,7,11,15,19

Step-by-step explanation:

Given the sum of these terms

=5a+10d=55

Hence a+2d=11

So T3=11 also given t4=5+t1+t2

Hence a+3d=5+a+a+d

So 2d=5+a

Adding a on both sides we get

a+2d=5+2a

But a+2d=t3=11

Hence 11=5+2a

So a=3

Also 2d=5+a hence d=4

Hence the series will be

3,7,11,15,19

Let the terms be a-2d, a-d, a, a+d and a+2d. Their sum 5a=55 so a=11.

=> now the AP is 11–2d, 11-d, 11, 11+d, 11+2d

T4 = T1+T2+5 so 11+d = 22–3d + 5 => 4d=16 or d=4

Ans is 3, 7, 11, 15, 19