Question

There are five terms in an Arithmetic Progression. The sum of these terms
is 55, and the fourth term is five more than the sum of the first two terms.
38.
35.
Find the terms of the Arithmetic progression.​

Answer 1

Given :   There are five terms in an Arithmetic Progression. The sum of these terms  is 55, and the fourth term is five more than the sum of the first two terms.

To find :  terms of the Arithmetic progression.​

Solution:

Let say AP is  

a , a + d , a + 2d  , a + 3d  , a  + 4d  

Sn = (n/2)(2a + (n-1)d )

Sum of 5 terms

= (5/2)(2a + 4d)  = 55

=> a + 2d  =  11

fourth term is five more than the sum of the first two terms.

=> a + 3d  = 5 + a + a + d

=>   2d  -  a  = 5

Adding both

=> 4d = 16

=> d  = 4

=> a  = 3

AP

3  ,  7  , 11 ,    15  , 19  

Learn More:

How to derive sum of n terms of an A.P? - Brainly.in

https://brainly.in/question/7849150

Find the sum of frist 51 terms of the AP whose 2nd term is 2 and 4th ...

https://brainly.in/question/7655866

write the next term of AP root2 ,root18........

https://brainly.in/question/8212323