Question

there are five terms in AP the sum of these terms is 55 and fourth term is 5 more than the sum of first two terms. find 5 terms of AP

Answer 1

Step-by-step explanation:

Let say AP is

a , a + d , a + 2d , a + 3d , a + 4d

Sn = (n/2)(2a + (n-1)d )

Sum of 5 terms

= (5/2)(2a + 4d) = 55

=> a + 2d = 11

fourth term is five more than the sum of the first two terms.

=> a + 3d = 5 + a + a + d

=> 2d - a = 5

Adding both

=> 4d = 16

=> d = 4

=> a = 3

AP

3 , 7 , 11 , 15 , 19

Answer 2

3,7,11,15,19 are the AP's