Question

There are five vessels, with equal capacities, each containing some milk The quantities of milk in the 5 vessels are in ratio 4:5:6: 7 : 8 such that the total quantity of milk in the vessels is equal to 75% of thetotal capacities of the 5 vessels.How many of the vessels are at lost 64% full of milk?​

Answer 1

Answer:

3 vessels

Step-by-step explanation:

let the milk contained by containers are

4x ,5x,6x, 7x and 8x

then total milk = 30 X

now let total capacity of the 5 vessels is 500 litres ( 100 litres each )

then

75% of 500 = 375 litres

now

30x = 375

X = 12.5

so the first container has = 12.5 * 4 = 50 litres

second = 12.5*5 = 62.5 litres

third = 12.5*6 = 75 litres

forth = 12.5*7 = 87.5 litres

fifth = 12.5*8 = 100 litres

there are three vessels which has more than 64% of milk

Answer 2

Given:

Total number of vessels = 5

Ratio of quantities = 4:5:6: 7 : 8

Total quantity = 75%

To Find:

How many of the vessels are at lost 64% full of milk?​

Solution:

Let the quantities of milk in the first vessel be = 4x,

Second = 5x,

Third = 6x,

Fourth = 7x and

Fifth = 8x

Therefore, total quantity of milk in the vessels -

= 4x + 5x + 6x+ 7x + 8x = 30x

Now,

Total capacity of the 5 vessels

= 30x (100/75)

= 40x

Capacity of each vessel is 8x

= 64% of 8x

= 64/100 x 8x

= 5.12x

Answer: The number of vessels of vessels which contain at least 64% of milk is three.