Question

There are five white balls, eight red balls, seven yellow balls and four green balls in a container. A ball is chosen at random. What is the probability of choosing neither white or green​

Answer 1

Answer:

37.5%

Step-by-step explanation:

5 white balls + 8 red balls + 7 yellow balls + 4 green balls = 24 balls.

Now, probability = $\frac{100}{24} = 4.16$%

So, 4.16% for per ball. ∵ 5 white balls + 4 green balls = (5+4)*4.16% = $37.5$%.

∴ The probability for choosing neither white nor green balls = 37.5%.

Hope it helps :}

Answer 2

The probability of choosing neither white or green​ is 5/8.

Given:

There are five white balls, eight red balls, seven yellow balls and four green balls in a container.

To find:

The probability of choosing neither white or green​.

Step-by-step explanation:

First, find the total number of balls in the container.

The total number of balls in the container is

5 white balls + 8 red balls + 7 yellow balls + 4 green balls = 24 balls.

The probability of choosing 5 white balls and 4 green balls is

=(5+4)/24

= 9/24

The probability of choosing neither white or green​ is

= 1-9/24

= 15/24

=5/8

Hence, the probability of choosing neither white or green​ is 5/8.

#SPJ2