Question

there are forty students in the class. find subject​

Answer 1

Answer:

Correct option is

A

100

Explanation:

Let A be the set of students in chemistry class and B be the set of students in physics class. It is given that n(A)=40 and n(B)=60.

If two classes meet at the same hour, then there will not be a common student sitting in both the classes.

Therefore, n(A∩B)=0

∴n(A∪B)=n(A)+n(B)−n(A∩B)

⇒n(A∪B)=40+60−0=100

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Answer 2

Answer:

students is the subject in the sentence