Question

there are four boxer colored red, blue, green and yellow. the four boxes weight 2½ kg, 1⅔ kg, 1 kg and 1¾ kg, not in that order. together, the red box and the green box weight 4¼ kg. the blue box is the lightest and the red box is the heaviest. what is the weight of each box?

Answer 1

Answer:

Weight of

Red Box = 2½ kg

Blue box = 1 kg

Green Box = 1¾ kg

Yellow Box = 1⅔ kg

Step-by-step explanation:

There are four boxes Red, Blue Green, Yellow.

Given weights of the boxes: 2½ kg, 1⅔ kg, 1 kg and 1¾ kg

Heaviest box = Red box = 2½ kg

Lightest box = Blue box = 1 kg

Red box + Green box = 4¼ kg

2½ kg + Green Box = 4¼ kg

Green Box = 4¼ kg - 2½ kg

                 = 1¾ kg

So, Yellow Box = 1⅔ kg

Therefore,

Weight of

Red Box = 2½ kg

Blue box = 1 kg

Green Box = 1¾ kg

Yellow Box = 1⅔ kg

Answer 2

Answer:

Weight of red box = $1\frac{1}{2}$ kg

Weight of green box = $1\frac{3}{4}$ kg

Weight of yellow box = $1\frac{2}{3}$ kg

Weight of blue box = $1$ kg

Step-by-step explanation:

Weight of the boxes in kg

$2\frac{1}{2}, 1\frac{2}{3}, 1,1\frac{3}{4}$

or, $\frac{5}{2},\frac{5}{3},1,\frac{7}{4}$

Weight of the red and green box

$=4\frac{1}{4}$ kg

$=\frac{17}{4}$ kg

If we add the first and the 4th in order

$\frac{5}{2}+\frac{7}{4}$

$=\frac{5\times 2}{2\times 2}+\frac{7}{4}$

$=\frac{10}{4}+\frac{7}{4}$

$=\frac{10+7}{4}$

$=\frac{17}{4}$ kg

Thus, the first and the fourth may be the red and green box

Given that the red box is heaviest

and among $\frac{5}{2}, \frac{7}{4}$

Since $\frac{5}{2}>\frac{7}{4}$   (By making denominator same and comparing the numerators)

Therefore, the weight of red box is $\frac{5}{2}$ or $1\frac{1}{2}$

Thus the green box is $\frac{7}{4}$ or $1\frac{3}{4}$

The lightest box is 1 kg box

Thus the weight of blue box is 1 kg

Weight of yellow box = $1\frac{2}{3}$ kg

Hope this helps.