Question

There are four brothers in a family. the sum of the ages of each combination of three brothers is 30,32,32 and 35. how old is the eldest brother

Answer 1

Answer:

35 is the more aged eldest brother

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Answer 2

Answer :

The older brother is 13 years old.

Explanation :

The ages of the four brothers are A, B, C, and D, where A is the age of the older brother. Then the sum of ages of each combination of three siblings can be expressed as:

A + B + C = 30

A + B + R = 32

A + C + R = 32

yes + c + d = 35

Adding the four equations we get:

3A + 2B + 2C + 2D = 129

Since we know that A, B, C, and D are positive integers, we can start trying different values ​​of A to see which one satisfies the equation above.

Starting from A = 10 we get:

3(10) + 2B + 2C + 2D = 129

2B + 2C + 2D = 99

This equation has no solution because the left-hand side is even and the right-hand side is odd.

If we prove A = 11, we get:

3(11) + 2B + 2C + 2D = 129

2B + 2C + 2D = 96

By simplifying the equation we get:

yes + c + d = 48

Using this equation and the given equation B + C + D = 35, we can conclude that A = 13, which corresponds to the older brother's age.

So the older brother is 13 years old.

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