There are four friends A,B,C and D. Initially all have some quantity of pure milk. If A gives 1/10th quantity of milk to B, then B gives 1/10th current quantity of milk to C, then C gives 1/10th of current quantity of milk to D, and at last then D gives his 1/10th of current quantity of milk to A, and now all have equal amount of milk. then find the % change of quantity of milk A w.r.t A was initially.
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At the beginning each had 1 amount of milk.
A => 1/10 to B and thus remains with :
1 - 1/10 = 9/10
B = The amount B currently has is :
1 + 1/10 = 11/10
He gives 1/10 of this to C
1/10 × 11/10 = 11/100
C=> The current amount of C is :
1 + 11/100 = 111/100
He gives 1/10 of this to D
1/10 × 111/100 = 111/1000
D => Current amount :
111/1000 + 1 = 1111/1000
He gives 1/10 of this to A
1/10 × 1111/1000 = 1111/10000
A => Change in A
9/10 + 1111/10000 = 10111/10000
Change in A :
10111/10000 - 1 = 111/10000
111/10000 × 100 = 1.11%
imsksingh2:
bro...i think you havent read the question properly....it has been already mention that final amount of all of them is same.....initial quantity doesnt really matters weather same or not....u havnt proved in ur qustion that final amout is equal for all....
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