Question

There are four numbers, 6 ,12,30 ,40
a.What is the greatest number of 6 digits which when divided by the numbers written above, 5 will be remainder in each case?​

Answer 1

Step-by-step explanation:

First we have to find the number which is divided by all the given numbers i.e 6,9,12,17

For that we have to find the LCM of those numbers.

The LCM of 6,9,12,17 is 612.

Now we shall find the largest 4-digit number which is divisible by 6,9,12,17 .

For that we have to find the largest 4-digit multiple of 612.

If we consider (612*17)= 10404 (since it is a 5-digit number we should reduce the multiple )

i.e (612*16)

=>9792

so it is the largest possible 4-digit number which is divisible by all the given numbers