Math, asked by devaraj66666, 10 months ago

There are four numbers.
If we leave out any one
number, the average of the
remaining three numbers
will be 45, 60, 65 or 70.
What is the average of all
four numbers?​

Answers

Answered by ufo97
0

Answer:

If the four numbers are A, B, C and D, then we know that

A + B + C = 45 × 3

A + B + D = 60 × 3

A + C + D = 65 × 3

B + C + D = 70 × 3

Now add them up to get 3A + 3B + 3C + 3D = (45 + 60 + 65 + 70) × 3

Which is A + B + C + D = (45 + 60 + 65 + 70) = 240. So their average is 240/4 = 60

Please mark me Brainliest answer

Answered by joinanu14
0

Answer:

60

Step-by-step explanation:

If the four numbers are A, B, C and D, then we know that

A + B + C = 45 × 3

A + B + D = 60 × 3

A + C + D = 65 × 3

B + C + D = 70 × 3

Now add them up to get 3A + 3B + 3C + 3D = (45 + 60 + 65 + 70) × 3

Which is A + B + C + D = (45 + 60 + 65 + 70) = 240. So their average is 240/4 = 60

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