There are four numbers such that first three of them form an arithmetic progression & the last three form a geometric progression. The sum of the first & third term is 2 & that of second & fourth is 26. What are these numbers.
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let the terms as a,b,c&d
now a+c/2=b=2/2=1
now 1+d=26,so d=25
b c &d form GP so √bd=c=5& a+c=2,so a=-3
these numbers are -3,1,5&25 respectively!!!
plz,mark it as brainlist if you satisfied!!!
now a+c/2=b=2/2=1
now 1+d=26,so d=25
b c &d form GP so √bd=c=5& a+c=2,so a=-3
these numbers are -3,1,5&25 respectively!!!
plz,mark it as brainlist if you satisfied!!!
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