Physics, asked by tayyibasiddiqui786, 8 months ago

there are four point charges placed at the vertices of a square of side a. an known charge is placed at the centre of the cubic square such that system is in equilibrium. also indicate the sign of unknown charge.​

Answers

Answered by panchalikar
0

Answer:

O is the center of  square and point P is at height h from the center

OA=OB=OC=OD=a

The magnitude of the electric force due to each charge is  

4πε  

0

​  

 

1

​  

 

a  

2

+h  

2

 

Qq

​  

 

The components of the the force perpendicular to OP sum up to zero because of the symmetrical distribution of charges about OP. Hence, the resultant force at P is upward along OP. The magnitude of the force is given by

R  

up

​  

=4×  

4πε  

0

​  

 

1

​  

 

h  

2

+a  

2

 

Qq

​  

cosθ

=  

πε  

0

​  

(h  

2

+a  

2

)

Qq

​  

 

h  

2

+a  

2

 

​  

 

h

​  

=  

πε  

0

​  

(h  

2

+a  

2

)  

3/2

 

Qqh

​  

 

F  

down

​  

=weight=mg

For equilibrium, mg=  

πε  

0

​  

(h  

2

+a  

2

)  

3/2

 

Qqh

​  

 

or Q=πε  

0

​  

 

hq

mg

​  

(h  

2

+a  

2

)  

3/2

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