Question

There are four terms in an A.P. In which sum of the first and last term is 13 and the

product of middle terms is 40. Then the terms of the given A.P​

Answer 1

Step-by-step explanation:

2,6,10,14. hope this is helpful . please mark me as brilliant

Answer 2

Step-by-step explanation:

$an = a + (n - 1) + d \\ 40 = 4 + 12 divide bothon2 \\ 20 = 2 + 6d \\ 20 - 2 = 6d \\ 18 = 6d \\ d = 4 \\ a.a + d.a + 2d.a + 3d \\ 2.6.10.14$