Question

There are hundred students in the class out of which 60 students drink tea, 50 student drink coffee and 30 students drink both tea and coffee if one student drawn at random then find the probability that the student drink either tea or coffee or both .give step by step explanation. wrong ans ko report hoga . atta he to he ans do .​

Answer 1

Answer:

Probability of students who either drink coffee and tea is 0.8

$\rule{250}1$

Explanation:

Given that, total number of students = 100

Out of 100 students; 60 students drink tea, 50 students drink coffee and 30 students drink both tea and coffee.

Formula Used:

⇒ Probability = $\sf{\frac{Number\:of\:favourable\:outcomes}{Total\:number\:of\:outcomes}}$

Now,

Probability (students who drink tea) = 60/100

→ 0.6

Probability (students who drink coffee) = 50/100

→ 0.5

Probability (students who drink both tea and coffee) = 30/100

→ 0.3

We have to find the probability; that the student drink either tea or coffee or both.

Now,

Probability (students who either drink tea or coffee) = Probability (students who drink tea) + Probability (students who drink coffee) - Probability (students who drink both tea and coffee)

Substitute the known values

→ 0.6 + 0.5 - 0.3

→ 1.1 - 0.3

→ $\boxed{\sf{0.8}}$

Answer 2

||✪✪ QUESTION ✪✪||

There are hundred students in the class out of which 60 students drink tea, 50 student drink coffee and 30 students drink both tea and coffee if one student drawn at random then find the probability that the student drink either tea or coffee or both ... ?

|| ✰✰ ANSWER ✰✰ ||

Probability :- Is the ratio of number of favorable outcomes to the total number of possible outcomes.

Given That :-

→ Total Students = 100 = Total possible outcomes .

Now,

(1) No. of Students Drink Tea = 60 = Favorable Outcomes.

→ Probability = (60/100) = 0.6 = P(T)

(2) No. of Students Drink coffee = 50 = Favorable Outcomes.

→ Probability = (50/100) = 0.5 = P(C)

(3) No. of Students Drink Both Tea and coffee = 30 = Favorable Outcomes.

→ probability = (30/100) = 0.3 = P(T ∩ C)

_____________________

Now, we Have To Find the probability that the student drink either tea or coffee or both = P(T ∪ C)

we know That :-

☛ P(T ∪ C) = P(T) + P(C) - P(T ∩ C)

Putting values now, we get :-

☞ P(T ∪ C) = (0.6) + (0.5) - (0.3)

☞ P(T ∪ C) = (1.1) - (0.3)

☞ P(T ∪ C) = (0.8)

Hence, The Required Probability is 0.8.