There are n geometric means between 9/8 and 8/81 such that 27(nth mean)=8(2nd mean) find the value of n
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3 & 81
⇒3,x,y,81
3y=x
2
x×81=y
2
9y
2
=x
2
y
2
=81x
9×81x=x
4
y
2
=3
4
⋅3
2
(x=9) (y=2y) (∴3,9,27,81).
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