There are n identical resister first all connected in series and then all connected in parallel.The ratio of total resistance in series to parallel will be......
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Answer:
n².
Explanation:
n resistors of resistance let R
so when they are kept in series total resistance is
R+R+R+R...n
=nR
when they are kept in parallel total resistance is
1/Req= 1/R + 1/R +1/R ...n
1/Req = n/R
Req = R/n
so ratio is nR/R/n
= n².
hope it helped.
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