Question

There are n points in a plane no three of which are in the same line excepting p points which are collinear. The number of triangles formed by joining them is? If anybody answer this question with process I will mark that answer as brainliest answer​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

hello mate..

Step-by-step explanation:

Number of lines formed any two points out of given N points =

n

C

2

and number of lines formed by joining any two points out of p collinear points =

p

C

2

. But these collinear points giving exactly one straight line passing through all of them.

Hence required number of straight lines =

n

C

2

−

n

C

2

+1

(ii) Number of triangles formed by joining any three points out of given n points =

n

C

3

and number of triangles formed by joining any three points out of p collinear points =

p

C

3

. But no triangle would be formed by joining any three points out of these p collinear points.

Hence the number of triangles formed =

n

C

3

−

p

C

3